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Beliebt Rechnen >

y^'+2y=x^2y^3

Lösung

y^{^{'}} + 2 y = x^{2} y^{3}

Lösung

y = \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}, y = - \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}

Schritte zur Lösung

y^{'} (x) + 2 y = x^{2} y^{3}

Solve Bernoulli ODE:

y = \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}, y = - \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}

y = \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}, y = - \frac{4}{8 x ^{2} + 4 x + 1 + 16 c _{1} e ^{4 x}}

Graph

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