integral from 3 to 1 of (-5x+9)

Lösung

\int_{3}^{1} (- 5 x + 9) d x

2

Schritte zur Lösung

\int_{3}^{1} - 5 x + 9 d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{3} - 5 x + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - (- \int_{1}^{3} 5 x d x + \int_{1}^{3} 9 d x)

\int_{1}^{3} 5 x d x = 20

\int_{1}^{3} 9 d x = 18

= - (- 20 + 18)

Vereinfache

= 2

\frac{\partial}{\partial x} (cos (n x) e^{n y})

\int \frac{arctan ( 5 x )}{1 + 25 x ^{2}} d x

d er i v a t i v e f (x) = \frac{x ^{4} + 5 x ^{2} + 10}{x ^{2}}

\int e^{x} - e^{- x} d x

\frac{\partial}{\partial x} (\frac{h ( x ) c}{x})