derivative 7e^x+4/(\sqrt[3]{x)}

解答

导数

7 e^{x} + \frac{4}{3 x}

7 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

求解步骤

\frac{d}{d x} (7 e^{x} + \frac{4}{3 x})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 e^{x}) + \frac{d}{d x} (\frac{4}{3 x})

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

\frac{d}{d x} (\frac{4}{3 x}) = - \frac{4}{3 x ^{\frac{4}{3}}}

= 7 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

t an g e n t f (x) = 110 x - 16 x^{2}, at 3.438

d er i v a t i v e \frac{x ^{4} - 16 x ^{2} - 16}{( x ^{2} - 4 ) ^{2}}

x y d y - (x^{2} + y^{2}) d x = 0

n = 1 \sum \infty \frac{1}{( 0.8 ) ^{n}}

\int_{0}^{2} x^{2} 4 - x^{2} d x