integral from 0 to 8 of x(1/8 x)

Lösung

\int_{0}^{8} x (\frac{1}{8} x) d x

\frac{64}{3}

Dezimale

21.33333 \dots

Schritte zur Lösung

\int_{0}^{8} x \frac{1}{8} x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int_{0}^{8} xx d x

Vereinfache

xx : x^{2}

= \frac{1}{8} \cdot \int_{0}^{8} x^{2} d x

Wende die Potenzregel an

= \frac{1}{8} [\frac{x ^{3}}{3}]_{0}^{8}

Berechne die Grenzen:

\frac{512}{3}

= \frac{1}{8} \cdot \frac{512}{3}

Vereinfache

= \frac{64}{3}

\frac{d}{d x} ((x^{3} - 5)^{5} (x^{5} + 7))

d er i v a t i v e \frac{2 x - 1}{2 ( x ^{2} - x )}

\frac{d}{d x} ((\frac{1}{x ^{3}} - \frac{2}{x}) (x^{2} + x))

\int - 2 sin (n x) d x

t an g e n t 4 x^{2} = ln (x - y) + 3, at x = 0