integral from-1 to 2 of (x+5)

解答

\int_{- 1}^{2} (x + 5) d x

\frac{33}{2}

十进制

16.5

求解步骤

\int_{- 1}^{2} x + 5 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x + \int_{- 1}^{2} 5 d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 5 d x = 15

= \frac{3}{2} + 15

化简

\frac{3}{2} + 15 : \frac{33}{2}

= \frac{33}{2}

d er i v a t i v e f (x) = 5.5 x + 2.2

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