(1+cos(t))y^'=(1+e-y)sin(t),y(0)=0

Lösung

(1 + cos (t)) y^{^{'}} = (1 + e - y) sin (t), y (0) = 0

y = - \frac{( e + 1 ) ( 1 + cos ( t ) )}{2} + 1 + e

Schritte zur Lösung

(1 + cos (t)) y^{'} (t) = (1 + e - y) sin (t)

Solve separable ODE:

y = - \frac{( e + 1 ) ( 1 + cos ( t ) )}{2} + 1 + e

y = - \frac{( e + 1 ) ( 1 + cos ( t ) )}{2} + 1 + e

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