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Beliebt Rechnen >

y^{''}+7y^'+12y=0,y(0)=a,y^'(0)=b

Lösung

y^{^{''}} + 7 y^{^{'}} + 12 y = 0, y (0) = a, y^{^{'}} (0) = b

Lösung

y = (a - (- b - 3 a)) e^{- 3 t} + (- b - 3 a) e^{- 4 t}

Schritte zur Lösung

y^{''} (t) + 7 y^{'} (t) + 12 y = 0

Solve linear ODE:

y = (a - (- b - 3 a)) e^{- 3 t} + (- b - 3 a) e^{- 4 t}

y = (a - (- b - 3 a)) e^{- 3 t} + (- b - 3 a) e^{- 4 t}

Graph

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