integral of (x^5)/(sqrt(x^2+8))

Lösung

\int \frac{x ^{5}}{x ^{2} + 8} d x

64 x^{2} + 8 - \frac{16}{3} (x^{2} + 8)^{\frac{3}{2}} + \frac{1}{5} (8 + x^{2})^{\frac{5}{2}} + C

Schritte zur Lösung

\int \frac{x ^{5}}{x ^{2} + 8} d x

Trigonometrische Substitution anwenden

= \int 1282 tan^{5} (u) sec (u) d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1282 \cdot \int tan^{5} (u) sec (u) d u

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= 1282 \cdot \int (- 1 + sec^{2} (u))^{2} tan (u) sec (u) d u

Wende U-Substitution an

= 1282 \cdot \int (- 1 + v^{2})^{2} d v

Multipliziere aus

(- 1 + v^{2})^{2} : 1 - 2 v^{2} + v^{4}

= 1282 \cdot \int 1 - 2 v^{2} + v^{4} d v

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 1282 (\int 1 d v - \int 2 v^{2} d v + \int v^{4} d v)

\int 1 d v = v

\int 2 v^{2} d v = \frac{2 v ^{3}}{3}

\int v^{4} d v = \frac{v ^{5}}{5}

= 1282 (v - \frac{2 v ^{3}}{3} + \frac{v ^{5}}{5})

Ersetze zurück

= 1282 sec (arctan (\frac{1}{2 2} x)) - \frac{2 sec ^{3} ( arctan ( \frac{1}{2 2} x ) )}{3} + \frac{sec ^{5} ( arctan ( \frac{1}{2 2} x ) )}{5}

Vereinfache

1282 sec (arctan (\frac{1}{2 2} x)) - \frac{2 sec ^{3} ( arctan ( \frac{1}{2 2} x ) )}{3} + \frac{sec ^{5} ( arctan ( \frac{1}{2 2} x ) )}{5} : 64 x^{2} + 8 - \frac{16}{3} (x^{2} + 8)^{\frac{3}{2}} + \frac{1}{5} (8 + x^{2})^{\frac{5}{2}}

= 64 x^{2} + 8 - \frac{16}{3} (x^{2} + 8)^{\frac{3}{2}} + \frac{1}{5} (8 + x^{2})^{\frac{5}{2}}

Füge eine Konstante zur Lösung hinzu

= 64 x^{2} + 8 - \frac{16}{3} (x^{2} + 8)^{\frac{3}{2}} + \frac{1}{5} (8 + x^{2})^{\frac{5}{2}} + C

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