What is the tangent of y=arctan(-x),\at x=4 ?

The tangent of y=arctan(-x),\at x=4 is y=-1/17 x-arctan(4)+4/17

tangent of y=arctan(-x),\at x=4

tangent of

y = arctan (- x), at x = 4

y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

Solution steps

Find the tangent point:

(4, - arctan (4))

Find the slope of

y = arctan (- x) : \frac{d y}{d x} = - \frac{1}{x ^{2} + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{17}

Find the line with slope m=

- \frac{1}{17}

and passing through

(4, - arctan (4)) : y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

y = - \frac{1}{17} x - arctan (4) + \frac{4}{17}

d er i v a t i v e y = x^{4} e^{2 x}

x \to 0 + lim (\frac{4}{x} - \frac{4}{∣ x ∣})

s l o p e (790, 77880), (970, 94440)

\int \frac{3}{37} x^{2} d x

\frac{d}{d x} (\frac{9}{4 4 x ^{3}})

What is the tangent of y=arctan(-x),\at x=4 ?
The tangent of y=arctan(-x),\at x=4 is y=-1/17 x-arctan(4)+4/17