laplacetransform tsin(0.89t)

Lösung

laplace transformation

t sin (0.89 t)

\frac{1.78 s}{( s ^{2} + 0.7921 ) ^{2}}

Schritte zur Lösung

L {t sin (0.89 t)}

Wende Laplace-Transformationstabelle an:

L {t^{k} f (t)} = (- 1)^{k} \frac{d ^{k}}{d s ^{k}} (L {f (t)})

Für

t sin (0.89 t) : f (t) = sin (0.89 t), k = 1

= (- 1)^{1} \frac{d}{d s} (L {sin (0.89 t)})

L {sin (0.89 t)} : \frac{0.89}{s ^{2} + 0.7921}

\frac{d}{d s} (\frac{0.89}{s ^{2} + 0.7921}) = - \frac{1.78 s}{( s ^{2} + 0.7921 ) ^{2}}

= (- 1)^{1} (- \frac{1.78 s}{( s ^{2} + 0.7921 ) ^{2}})

= \frac{1.78 s}{( s ^{2} + 0.7921 ) ^{2}}

d er i v a t i v e \frac{5}{8 t}

\frac{\partial}{\partial y} (x^{2} y^{3} z)

d er i v a t i v e y = - 3 x + 5

k = 1 \sum \infty 3^{k} 7

\frac{d y}{d x} = 4 y + x^{2} + 7