y^{'''}-y^{''}+7y^'-7y=0

解答

y^{^{'''}} - y^{^{''}} + 7 y^{^{'}} - 7 y = 0

y = c_{1} e^{t} + c_{2} cos (7 t) + c_{3} sin (7 t)

求解步骤

y^{'''} (t) - y^{''} (t) + 7 y^{'} (t) - 7 y = 0

求解线性方程:

y = c_{1} e^{t} + c_{2} cos (7 t) + c_{3} sin (7 t)

y = c_{1} e^{t} + c_{2} cos (7 t) + c_{3} sin (7 t)

x \to 0 lim (x^{3} x)

\int_{0}^{5} \frac{x + y}{55} d x

\frac{\partial}{\partial x} (4 arctan (\frac{y}{x}))

\frac{d}{d x} (sin (e^{x} (x^{2} - x)))

t an g e n t 2 x^{2} - 2 x - 4, at x = 1