What is the inverse of f(x)=(sqrt(3x-1))/5 ?

The inverse of f(x)=(sqrt(3x-1))/5 is (25x^2+1)/3

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inverse of f(x)=(sqrt(3x-1))/5

inverse

f (x) = \frac{3 x - 1}{5}

\frac{25 x ^{2} + 1}{3}

Solution steps

y = \frac{3 x - 1}{5}

Replace

x

with

y

x = \frac{3 y - 1}{5}

Solve for

y, x = \frac{3 y - 1}{5}

\frac{25 x ^{2} + 1}{3}

f (x) = 15 x^{2} + 2 x - 8

f (x) = 1980 \cdot 0.9 7^{x}

f (x) = 2 x^{2} - 13 x + 15

f (x) = \frac{4 x - 5}{3 x - 1}

f (x) = (x - 3)^{3} + 5

What is the inverse of f(x)=(sqrt(3x-1))/5 ?
The inverse of f(x)=(sqrt(3x-1))/5 is (25x^2+1)/3