What is the inverse of f(x)=16x^2-24x+6 ?

The inverse of f(x)=16x^2-24x+6 is (3+sqrt(x+3))/4 ,(3-sqrt(x+3))/4

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inverse of f(x)=16x^2-24x+6

inverse

f (x) = 16 x^{2} - 24 x + 6

\frac{3 + x + 3}{4}, \frac{3 - x + 3}{4}

Solution steps

y = 16 x^{2} - 24 x + 6

Replace

x

with

y

x = 16 y^{2} - 24 y + 6

Solve for

y, x = 16 y^{2} - 24 y + 6

\frac{3 + x + 3}{4}, \frac{3 - x + 3}{4}

f (x) = x^{2} + 2 x - 3, x \leq 2

\frac{x - 4}{x + 7}

f (x) = \frac{3 - 5 x}{4}

\frac{( 2 x - 5 )}{( 4 x + 3 )}

\frac{- 3 - 4 x}{2 + 2 x}

What is the inverse of f(x)=16x^2-24x+6 ?
The inverse of f(x)=16x^2-24x+6 is (3+sqrt(x+3))/4 ,(3-sqrt(x+3))/4