extreme f(x)=x^3-75x+10

Lösung

extrempunkte

f (x) = x^{3} - 75 x + 10

Maximum (- 5, 260), Minimum (5, - 240)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 75

Intervalle finden:

Ansteigend

: - \infty < x < - 5,

Absteigend

: - 5 < x < 5,

Ansteigend

: 5 < x < \infty

Stecke

x = - 5

x^{3} - 75 x + 10 : 260

Maximum (- 5, 260)

Stecke

x = 5

x^{3} - 75 x + 10 : - 240

Minimum (5, - 240)

Maximum (- 5, 260), Minimum (5, - 240)

a sy m pt o t es f (x) = \frac{9 x - 21}{15 x + 35}

d o main f (x) = - (x - 6) (x + 6) (x + 3)

a sy m pt o t es sec (2 x - 3 π)

d o main f (x) = (x - 3) (2 x + 6) 7 x^{3}

d o main - 2 x^{2} + 5 x - 6