求反函数 g(2)=(2x+3)/(x-1)

解答

求反函数

g (2) = \frac{2 x + 3}{x - 1}

\frac{3 + x}{x - 2}

求解步骤

y = \frac{2 x + 3}{x - 1}

用

y

替代

x

x = \frac{2 y + 3}{y - 1}

求解

y, x = \frac{2 y + 3}{y - 1}

\frac{3 + x}{x - 2}

in v erse f (x) = 3 x - 3 + \frac{7}{5}

in v erse 3 2^{\frac{2}{5}}

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in v erse - \frac{( x - 11 )}{14}, x \leq \frac{14}{11}