What is the inverse of f(x)=log_{6}(x+1)-8 ?

The inverse of f(x)=log_{6}(x+1)-8 is 6^{x+8}-1

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inverse of f(x)=log_{6}(x+1)-8

inverse

f (x) = lo g_{6} (x + 1) - 8

6^{x + 8} - 1

Solution steps

y = lo g_{6} (x + 1) - 8

Replace

x

with

y

x = lo g_{6} (y + 1) - 8

Solve for

y, x = lo g_{6} (y + 1) - 8

6^{x + 8} - 1

\frac{- 2 s + 6}{s ^{2} + 64}

f (x) = \frac{5 - 3 x}{2 x + 3}

y = - 200 + 200 x

\frac{1}{ln ( 2 x + 1 )}

f (x) = 2 x + 2 = 3 y

What is the inverse of f(x)=log_{6}(x+1)-8 ?
The inverse of f(x)=log_{6}(x+1)-8 is 6^{x+8}-1