What is the domain of 1/(x^2+x-6) ?

The domain of 1/(x^2+x-6) is x 2

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domain of 1/(x^2+x-6)

domain

\frac{1}{x ^{2} + x - 6}

x < - 3 or - 3 < x < 2 or x > 2

Interval Notation

(- \infty, - 3) \cup (- 3, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 3

The function domain

x < - 3 or - 3 < x < 2 or x > 2

\frac{1}{3 x ^{2} + 11 x - 20}

f (x) = \frac{x ^{2}}{x ^{2} + x + 1}

f (x) = \frac{x ^{2} + 9 x + 18}{2 x ^{2} - 18}

f (x) = ln (9 t^{2} - 64)

f (x) = \frac{- 18 x - 21}{5 x + 6}

What is the domain of 1/(x^2+x-6) ?
The domain of 1/(x^2+x-6) is x<-3\lor-3<x<2\lor x>2