What is the domain of f(x)=((\sqrt[4]{x}))/(25-x) ?

The domain of f(x)=((\sqrt[4]{x}))/(25-x) is 0 25

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domain of f(x)=((\sqrt[4]{x}))/(25-x)

domain

f (x) = \frac{( 4 x )}{25 - x}

0 \leq x < 25 or x > 25

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = 25

Combine real regions and undefined points for final function domain

0 \leq x < 25 or x > 25

f (x) = \frac{2 x - 1}{x ^{2} + 2 x}

3 x^{4} x

x^{2} - 12 x + 58

5 x^{3} + 2 x^{2} - 7 x

\frac{1}{x e ^{x}}

What is the domain of f(x)=((\sqrt[4]{x}))/(25-x) ?
The domain of f(x)=((\sqrt[4]{x}))/(25-x) is 0<= x<25\lor x>25