extreme x^2+8x+18

Lösung

extrempunkte

x^{2} + 8 x + 18

Minimum (- 4, 2)

Schritte zur Lösung

f^{'} (x) = 2 x + 8

Intervalle finden:

Absteigend

: - \infty < x < - 4,

Ansteigend

: - 4 < x < \infty

Stecke

x = - 4

x^{2} + 8 x + 18 : 2

Minimum (- 4, 2)

e x t re m e f (x) = x e^{- \frac{x}{2}}

e x t re m e 1 - x + 1 + x + 2 x

e x t re m e f (x) = x e^{- \frac{x}{3}}

e x t re m e f (x) = x^{3} + y^{3} - 3 x^{2} - 3 y^{2} - 9 x

e x t re m e f (x) = 2 x^{3} - 36 x^{2} + 210 x - 15