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Popular >

extreme f(x)=2e^{x^2-2x+1}

Solution

extreme points

f (x) = 2 e^{x^{2} - 2 x + 1}

Solution

Minimum (1, 2)

Solution steps

f^{'} (x) = 2 e^{x^{2} - 2 x + 1} (2 x - 2)

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 e^{x^{2} - 2 x + 1} : 2

Minimum (1, 2)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2e^{x^2-2x+1} ?
The extreme f(x)=2e^{x^2-2x+1} is Minimum(1,2)