What is the extreme f(x,y)=2-x^2-y^2 ?

The extreme f(x,y)=2-x^2-y^2 is Maximum(0,0)

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extreme f(x,y)=2-x^2-y^2

extreme points

f (x, y) = 2 - x^{2} - y^{2}

Maximum (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 4

Check the sign of at each critical point

Check critical point

(0, 0) :

Maximum

Maximum (0, 0)

f (x, y) = 400 - 64 x^{2} - 81 y^{2}

f (x) = x y^{2} + 3 x^{- 3 x}

f (x) = \frac{5}{x + 7}

5 x^{2} + 12 x + 9

f (x) = 6 x^{3} - 72 x + 10

What is the extreme f(x,y)=2-x^2-y^2 ?
The extreme f(x,y)=2-x^2-y^2 is Maximum(0,0)