inflection f(x)=x^4-8x^2+3

Lösung

wendepunkte

f (x) = x^{4} - 8 x^{2} + 3

(- \frac{2}{3}, - \frac{53}{9}), (\frac{2}{3}, - \frac{53}{9})

Schritte zur Lösung

f^{''} (x) = 12 x^{2} - 16

Intervalle finden:

Konkav steigend

: - \infty < x < - \frac{2}{3},

Konkav fallend

: - \frac{2}{3} < x < \frac{2}{3},

Konkav steigend

: \frac{2}{3} < x < \infty

Stecke

x = - \frac{2}{3}

x^{4} - 8 x^{2} + 3 : - \frac{53}{9}

(- \frac{2}{3}, - \frac{53}{9})

Stecke

x = \frac{2}{3}

x^{4} - 8 x^{2} + 3 : - \frac{53}{9}

(\frac{2}{3}, - \frac{53}{9})

(- \frac{2}{3}, - \frac{53}{9}), (\frac{2}{3}, - \frac{53}{9})

a sy m pt o t es x^{2} + 5 x - 3600

cr i t i c a l sin (x + \frac{5}{2})

d o main f (x) = 2 (x - 2)^{2} - 3

p a r i t y f (x) = - 9 x - x^{7}

r an g e arcsec (x)