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Popular >

extreme F(x)=(5x^2)/(x^2-16)

Solution

extreme points

F (x) = \frac{5 x ^{2}}{x ^{2} - 16}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{160 x}{( x ^{2} - 16 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 0

into

\frac{5 x ^{2}}{x ^{2} - 16} : 0

Maximum (0, 0)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme F(x)=(5x^2)/(x^2-16) ?
The extreme F(x)=(5x^2)/(x^2-16) is Maximum(0,0)