extreme f(x)=2x+(32)/x

Lösung

extrempunkte

f (x) = 2 x + \frac{32}{x}

Maximum (- 4, - 16), Minimum (4, 16)

Schritte zur Lösung

f^{'} (x) = 2 - \frac{32}{x ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 4,

Absteigend

: - 4 < x < 0,

Absteigend

: 0 < x < 4,

Ansteigend

: 4 < x < \infty

Stecke

x = - 4

2 x + \frac{32}{x} : - 16

Maximum (- 4, - 16)

Stecke

x = 4

2 x + \frac{32}{x} : 16

Minimum (4, 16)

Maximum (- 4, - 16), Minimum (4, 16)

e x t re m e f (x) = \frac{x ^{3}}{3} - x^{2} - 3 x - 1, - 7 \leq x \leq 7

e x t re m e y = (x - 4)^{4} (x + 3)^{3}

e x t re m e - x^{3} + 6 x^{2}

e x t re m e f (x) = 6 x^{3} - 21 x^{2} + 36 x - 5

e x t re m e f (x) = \frac{1}{3} x^{3} - 2 x^{2} - 5 x - 10