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Beliebt Funktionen >

extreme f(x)=x^3-3x^2+3x+7

Lösung

extrempunkte

f (x) = x^{3} - 3 x^{2} + 3 x + 7

Lösung

Sattel (1, 8)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 6 x + 3

Intervalle finden:

Ansteigend

: - \infty < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = 1

in

x^{3} - 3 x^{2} + 3 x + 7 : 8

Sattel (1, 8)

Graph

Beliebte Beispiele

extreme f(x)=(t-4t^2)^{1/3}

e x t re m e f (x) = (t - 4 t^{2})^{\frac{1}{3}}

extreme f(x,y)=1-(x^2+y^2)

e x t re m e f (x, y) = 1 - (x^{2} + y^{2})

extreme x/((x^2+1))

e x t re m e \frac{x}{( x ^{2} + 1 )}

extreme f(x)=x^3-3x^2+3x-1

e x t re m e f (x) = x^{3} - 3 x^{2} + 3 x - 1

extreme f(x)=4x^5-7x^2+8

e x t re m e f (x) = 4 x^{5} - 7 x^{2} + 8