extreme x^2-2x-1

解答

极值点

x^{2} - 2 x - 1

极小值 (1, - 2)

求解步骤

f^{'} (x) = 2 x - 2

Find intervals:

递减

: - \infty < x < 1,

递增

: 1 < x < \infty

将

x = 1

代入

x^{2} - 2 x - 1 : - 2

极小值 (1, - 2)

e x t re m e f (x) = 5 x^{3} - 5 x^{2} - 5 x + 9

e x t re m e f (x) = 408 - x x

e x t re m e f (x) = x^{2} - 2 x + 6

e x t re m e f (x) = e^{- (x^{2} + y^{2})} (x^{2} + 2 y^{2})

e x t re m e \frac{X - 1}{X + 1}