What is the extreme f(x)=x^6+x/6 ?

The extreme f(x)=x^6+x/6 is Minimum(-1/(\sqrt[5]{36)},-5/(36\sqrt[5]{36)})

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extreme f(x)=x^6+x/6

extreme points

f (x) = x^{6} + \frac{x}{6}

Solution steps

f^{'} (x) = 6 x^{5} + \frac{1}{6}

Find intervals:

Decreasing

Increasing

Plug

into

y = - 57.17 x^{2} + 621.83 x + 1089

f (x) = x + \frac{( 1 )}{( x )}, 0.2 \leq x \leq 4

f (x, y) = ln (1 + 4 x^{2} + 6 y^{2})

f (x) = x^{2} - 6 x y + 2 y^{2} + 10 x + 2 y - 5

25 x

What is the extreme f(x)=x^6+x/6 ?
The extreme f(x)=x^6+x/6 is Minimum(-1/(\sqrt[5]{36)},-5/(36\sqrt[5]{36)})