What is the extreme f(x)=-x^4-6x ?

The extreme f(x)=-x^4-6x is Maximum(-\sqrt[3]{3/2},-(3/2)^{4/3}+3\sqrt[3]{12})

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extreme f(x)=-x^4-6x

extreme

Maximum (- 3 \frac{3}{2}, - (\frac{3}{2})^{\frac{4}{3}} + 3312)

Solution steps

f^{'} (x) = - 4 x^{3} - 6

Find intervals:

Increasing

: - \infty < x < - 3 \frac{3}{2},

Decreasing

: - 3 \frac{3}{2} < x < \infty

Plug

x = - 3 \frac{3}{2}

into

- x^{4} - 6 x : - (\frac{3}{2})^{\frac{4}{3}} + 3312

Maximum (- 3 \frac{3}{2}, - (\frac{3}{2})^{\frac{4}{3}} + 3312)

What is the extreme f(x)=-x^4-6x ?
The extreme f(x)=-x^4-6x is Maximum(-\sqrt[3]{3/2},-(3/2)^{4/3}+3\sqrt[3]{12})