invers 4cos(x)+1

Lösung

invers

4 cos (x) + 1

arccos (\frac{x - 1}{4})

Schritte zur Lösung

Löse nach

cos (x), y = 4 cos (x) + 1

cos (x) = \frac{y - 1}{4}

cos (a) = b \Rightarrow a = arccos (b)

arccos (\frac{y - 1}{4})

Ersetze

y = x

arccos (\frac{x - 1}{4})

e x t re m e f (x) = 3 x - x^{2}

s l o p e 2 x + 4 y = 8

in v erse f (x) = - 6 x - 1

in t erce pt s f (x) = x^{2} - 9

d o main f (x) = - x + 5