What is the domain of f(x)=sqrt(-x^2+3x-1) ?

The domain of f(x)=sqrt(-x^2+3x-1) is (-sqrt(5)+3)/2 <= x<= (sqrt(5)+3)/2

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domain of f(x)=sqrt(-x^2+3x-1)

domain

f (x) = - x^{2} + 3 x - 1

\frac{- 5 + 3}{2} \leq x \leq \frac{5 + 3}{2}

Interval Notation

[\frac{- 5 + 3}{2}, \frac{5 + 3}{2}]

Solution steps

Find non-negative values for radicals:

\frac{- 5 + 3}{2} \leq x \leq \frac{5 + 3}{2}

The function domain

\frac{- 5 + 3}{2} \leq x \leq \frac{5 + 3}{2}

f (x) = 2 - x - x^{3}

y = x^{3} - 5

f (x) = 2 x + 11

f (x) = 2 x - 0.5 x^{2}

f (x) = \frac{2 x + 4}{4 x + 5}

What is the domain of f(x)=sqrt(-x^2+3x-1) ?
The domain of f(x)=sqrt(-x^2+3x-1) is (-sqrt(5)+3)/2 <= x<= (sqrt(5)+3)/2