What is the domain of 1/(\frac{9){x-2}+3} ?

The domain of 1/(\frac{9){x-2}+3} is x 2

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domain of 1/(\frac{9){x-2}+3}

domain

\frac{1}{\frac{9}{x - 2} + 3}

x < - 1 or - 1 < x < 2 or x > 2

Interval Notation

(- \infty, - 1) \cup (- 1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 2

The function domain

x < - 1 or - 1 < x < 2 or x > 2

\frac{x + 8}{x ^{2} - 16 x + 64}

y = cos (x)

y = x^{3} - 3

f (x) = \frac{2 x}{x + 1}

f (x) = ln (\frac{x}{x - 1})

What is the domain of 1/(\frac{9){x-2}+3} ?
The domain of 1/(\frac{9){x-2}+3} is x<-1\lor-1<x<2\lor x>2