What is the domain of f(x)=-sqrt(16-x^2) ?

The domain of f(x)=-sqrt(16-x^2) is -4<= x<= 4

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domain of f(x)=-sqrt(16-x^2)

domain

f (x) = - 16 - x^{2}

- 4 \leq x \leq 4

Interval Notation

[- 4, 4]

Solution steps

Find non-negative values for radicals:

- 4 \leq x \leq 4

The function domain

- 4 \leq x \leq 4

x^{5} - 3 x^{3} - 2

f (x) = \frac{7}{x} - 4

f (x) = 3 x + 5

f (x) = - 5 x + 2 - 1

f (x) = sin (2 sin (2 x))

What is the domain of f(x)=-sqrt(16-x^2) ?
The domain of f(x)=-sqrt(16-x^2) is -4<= x<= 4