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Popular >

distance (2,1),(4,-4)

Solution

distance

(2, 1), (4, - 4)

Solution

29

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 1)

and

(4, - 4)

is

= (4 - 2)^{2} + (- 4 - 1)^{2}

Simplify

= 29

Popular Examples

inverse of y=-10x inverse

y = - 10 x

domain of (2x^2+14x+29)/(x^2+7x+10)domain

\frac{2 x ^{2} + 14 x + 29}{x ^{2} + 7 x + 10}

parallel 5x-2y=4,(2,-4)parallel

5 x - 2 y = 4, (2, - 4)

critical f(x)=x^3-48x critical points

f (x) = x^{3} - 48 x

shift csc(x)shift

csc (x)

Frequently Asked Questions (FAQ)

What is the distance (2,1),(4,-4) ?
The distance (2,1),(4,-4) is square root of 29