What is the critical f(x)=x^4-5x^2+4 ?

The critical f(x)=x^4-5x^2+4 is x=-sqrt(5/2),x=0,x=sqrt(5/2)

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critical f(x)=x^4-5x^2+4

critical points

f (x) = x^{4} - 5 x^{2} + 4

x = - \frac{5}{2}, x = 0, x = \frac{5}{2}

Solution steps

x^{4} - 5 x^{2} + 4

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{5}{2}, x = 0, x = \frac{5}{2}

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 5 x^{2} + 4 : - \infty < x < \infty

All critical points are in domain

x = - \frac{5}{2}, x = 0, x = \frac{5}{2}

\frac{x + 1}{x ^{2} + x + 1}

y = 2 x + 1 (3.1)

lo g_{3} (4^{x} - 4)

f (x) = (x - 3) x^{2}

f (x) = 1 - 2 x

What is the critical f(x)=x^4-5x^2+4 ?
The critical f(x)=x^4-5x^2+4 is x=-sqrt(5/2),x=0,x=sqrt(5/2)