What is the perpendicular y=3x-4,(-4,5) ?

The perpendicular y=3x-4,(-4,5) is y=-1/3 x+11/3

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perpendicular y=3x-4,(-4,5)

perpendicular

y = 3 x - 4, (- 4, 5)

y = - \frac{1}{3} x + \frac{11}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 4

that passes through

(- 4, 5)

Find the slope of

y = 3 x - 4 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 4, 5) : y = - \frac{1}{3} x + \frac{11}{3}

y = - \frac{1}{3} x + \frac{11}{3}

f (x) = \frac{3 x + 1}{4 x ^{2} - 1}

(- 4, - 3), (6, - 7)

f (x) = \frac{9}{x ^{2} - 16}

\frac{1}{( x - 3 ) ^{3}}

\frac{2}{x + 7}

What is the perpendicular y=3x-4,(-4,5) ?
The perpendicular y=3x-4,(-4,5) is y=-1/3 x+11/3