steigung 2(1.2)

Lösung

steigung

2 (1.2)

m = 0

Schritte zur Lösung

y = 2 \cdot 1.2

Schreibe um

y = 0 x + 2 \cdot 1.2

EN : Sl o p e L in e a r St an d a r d F or m St a t e Sl o p e Sp ec i f i c 1 Eq

m = 0

a sy m pt o t es f (x) = \frac{2 x}{x}

in v erse f (x) = 4 x + 1

p a r a ll e l 3 x - 2 y = 6

in t erce pt s f (x) = 6 x + 5 y = 0

e x t re m e f (x) = x^{2} ln (x)