值域-sqrt(x+3)

解答

值域

- x + 3

f (x) \leq 0

间隔符号

(- \infty, 0]

求解步骤

- c a x + b + k

形式的根函数的值域为

f (x) \leq k

k = 0

f (x) \leq 0

e x t re m e y = x^{3} + y^{3} - x - y - 2 = 0

in v erse f (x) = \frac{x}{- 8 x + 3}

mi d p o in t (6, 97), (- 4, - 77)

in v erse f (x) = \frac{1}{x - 10}

in v erse cot (x)