What is the domain of y=(x^2-1)/(x-1) ?

The domain of y=(x^2-1)/(x-1) is x 1

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domain of y=(x^2-1)/(x-1)

domain

y = \frac{x ^{2} - 1}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = x^{3} - 3 x + 5

- lo g_{5} (x - 10) - 1

lo g_{4} (x - 2)

f (x) = \frac{6 - 3 x}{x ^{2} + 3 x - 2}

f^{8}

What is the domain of y=(x^2-1)/(x-1) ?
The domain of y=(x^2-1)/(x-1) is x<1\lor x>1