What is the domain of (2x-9)/(3x^2-75) ?

The domain of (2x-9)/(3x^2-75) is x 5

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domain of (2x-9)/(3x^2-75)

domain

\frac{2 x - 9}{3 x ^{2} - 75}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{x ^{3}}{3} - 9 x

f (x) = \frac{1}{2.1 x - 6 x ^{2}}

\frac{5 x + 2}{x - 9}

3 x^{2} - 4 x + 7

- \frac{3}{4} x + 2

What is the domain of (2x-9)/(3x^2-75) ?
The domain of (2x-9)/(3x^2-75) is x<-5\lor-5<x<5\lor x>5