extreme f(x)=(x^2)/(x^2+1)

Lösung

extrempunkte

f (x) = \frac{x ^{2}}{x ^{2} + 1}

Minimum (0, 0)

Schritte zur Lösung

f^{'} (x) = \frac{2 x}{( x ^{2} + 1 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

\frac{x ^{2}}{x ^{2} + 1} : 0

Minimum (0, 0)

e x t re m e f (x, y) = 7 + x + 4 y - x^{2} - 4 y^{2}

e x t re m e f (x) = 2 x^{3} - 6 x + 6 x y^{2}

e x t re m e f (x, y) = \frac{2 x - y}{( x - 2 ) ^{2} + ( y - 1 ) ^{2}}

e x t re m e f (x) = \frac{x}{( x ^{2} + 1 )}

e x t re m e f (x, y) = 2 x^{3} + 2 y^{3} - 9 x^{2} + 3 y^{2} - 12 y