extreme f(x)=2x^3-2x^2-16x+1

Lösung

extrempunkte

f (x) = 2 x^{3} - 2 x^{2} - 16 x + 1

Maximum (- \frac{4}{3}, \frac{379}{27}), Minimum (2, - 23)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 4 x - 16

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{4}{3},

Absteigend

: - \frac{4}{3} < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = - \frac{4}{3}

2 x^{3} - 2 x^{2} - 16 x + 1 : \frac{379}{27}

Maximum (- \frac{4}{3}, \frac{379}{27})

Stecke

x = 2

2 x^{3} - 2 x^{2} - 16 x + 1 : - 23

Minimum (2, - 23)

Maximum (- \frac{4}{3}, \frac{379}{27}), Minimum (2, - 23)

e x t re m e f (x) = e^{x + y}

e x t re m e f (x) = 4 x^{3} - x^{2} - 4 x + 3

e x t re m e f (x) = 2 x^{3} - 3 x^{2} - 12 x + 12

e x t re m e f (x, y) = 2 x^{3} - 6 x + 6 x y^{2}

e x t re m e f (x, y) = e^{x} ln (y)