渐近线 f(x)=(-2x+10)/(x-4)

解答

渐近线

f (x) = \frac{- 2 x + 10}{x - 4}

垂直 : x = 4, 水平 : y = - 2

求解步骤

\frac{- 2 x + 10}{x - 4}

的垂直渐近线:

x = 4

\frac{- 2 x + 10}{x - 4}

的水平渐近线:

y = - 2

Slant Asymptotes of

\frac{- 2 x + 10}{x - 4} :

无

垂直 : x = 4, 水平 : y = - 2

r an g e f (x) = - x^{2} + 6 x - 8

d o main 2 - x

d o main \frac{x ^{3} - 2 x ^{2} - 3 x}{x - 3}

e x t re m e f (x) = 2 x^{3} - 2 x^{2} - 2 x + 3

r an g e f (x) = x^{2} - 12 x + 5