3x^2-5x+3y^2+5y-8=0

解

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

(a, b) = (\frac{5}{6}, - \frac{5}{6}), r = \frac{73}{3 2}

解答ステップ

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

3 x^{2} - 5 x + 3 y^{2} + 5 y - 8 = 0

を標準的な円のequationの形式で書き換える

(x - \frac{5}{6})^{2} + (y - (- \frac{5}{6}))^{2} = (\frac{73}{3 2})^{2}

ゆえに円の特性は:

(a, b) = (\frac{5}{6}, - \frac{5}{6}), r = \frac{73}{3 2}