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Beliebt Geometry >

center x^2+y^2+14x-12y+4=0

Lösung

center

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

Lösung

(- 7, 6)

Schritte zur Lösung

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

Rewrite

x^{2} + y^{2} + 14 x - 12 y + 4 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 6)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 7, 6), r = 9

And the center is:

(- 7, 6)

Graph

Beliebte Beispiele

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ce n t er x^{2} + y^{2} - 10 x - 16 y + 53 = 0

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