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Beliebt Geometry >

center x^2+(y+4)^2=7

Lösung

center

x^{2} + (y + 4)^{2} = 7

Lösung

(0, - 4)

Schritte zur Lösung

x^{2} + (y + 4)^{2} = 7

Rewrite

x^{2} + (y + 4)^{2} = 7

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = 7

And the center is:

(0, - 4)

Graph

Beliebte Beispiele

center (x+6)^2+(y-7)^2=81

ce n t er (x + 6)^{2} + (y - 7)^{2} = 81

center (x-1.5)^2+(y+0.5)^2=110.5

ce n t er (x - 1.5)^{2} + (y + 0.5)^{2} = 110.5

center (x-7)^2+(y+4)^2=9

ce n t er (x - 7)^{2} + (y + 4)^{2} = 9

center (x+2)^2+(y-4)^2=16

ce n t er (x + 2)^{2} + (y - 4)^{2} = 16

center x^2+y^2-6y=16

ce n t er x^{2} + y^{2} - 6 y = 16