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Beliebt Geometry >

center x^2+y^2+6x-2y=0

Lösung

center

x^{2} + y^{2} + 6 x - 2 y = 0

Lösung

(- 3, 1)

Schritte zur Lösung

x^{2} + y^{2} + 6 x - 2 y = 0

Rewrite

x^{2} + y^{2} + 6 x - 2 y = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 1)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 1), r = 10

And the center is:

(- 3, 1)

Graph

Beliebte Beispiele

center (x-5)^2+(y-3)^2=64

ce n t er (x - 5)^{2} + (y - 3)^{2} = 64

center 12x^2+12y^2-18x+4y-5=0

ce n t er 12 x^{2} + 12 y^{2} - 18 x + 4 y - 5 = 0

center (x-3)^2+(y-4)^2=49

ce n t er (x - 3)^{2} + (y - 4)^{2} = 49

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ce n t er x^{2} - 7 x + y^{2} + 8 y - 14 = 0

center 3(x-5)^2+3(y+9)^2=48

ce n t er 3 (x - 5)^{2} + 3 (y + 9)^{2} = 48