x=4y^2+8y+2

Lösung

x = 4 y^{2} + 8 y + 2

(h, k) = (- 2, - 1), p = \frac{1}{16}

Schritte zur Lösung

x = 4 y^{2} + 8 y + 2

Rewrite

x = 4 y^{2} + 8 y + 2

in the standard form

4 \cdot \frac{1}{16} (x - (- 2)) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 1), p = \frac{1}{16}

y^{2} = 40 x

49 y^{2} - 392 x + 28 y + 732 = 0

(y - 4)^{2} = 16 x

x = y^{2} + 6

6 x^{2} + 12 x + y + 13 = 0