x^2+10x-y+15=0

Lösung

x^{2} + 10 x - y + 15 = 0

(h, k) = (- 5, - 10), p = \frac{1}{4}

Schritte zur Lösung

x^{2} + 10 x - y + 15 = 0

Rewrite

x^{2} + 10 x - y + 15 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 10)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 10), p = \frac{1}{4}

- x^{2} + 12 x - 12 y - 96 = 0

x + 3 = y^{2}

n = B (- h^{2} + a)

(y - 1)^{2} = x + 1

\frac{x - y}{x} = x + 1