de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

radius x^2+(y-5)^2-4=0

Lösung

radius

x^{2} + (y - 5)^{2} - 4 = 0

Lösung

r = 2

Schritte zur Lösung

x^{2} + (y - 5)^{2} - 4 = 0

Rewrite

x^{2} + (y - 5)^{2} - 4 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 5)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 5), r = 2

And the radius is:

r = 2

Graph

Beliebte Beispiele

radius (x-1)^2+y^2=9

r a d i u s (x - 1)^{2} + y^{2} = 9

radius 4x^2+4y^2+24x-32y+91=0

r a d i u s 4 x^{2} + 4 y^{2} + 24 x - 32 y + 91 = 0

radius (x-2.5)^2+(y-0.5)^2=14.5

r a d i u s (x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

radius (x-5)^2+(y-12)^2=9

r a d i u s (x - 5)^{2} + (y - 12)^{2} = 9

radius 4x^2+4y^2-16=0

r a d i u s 4 x^{2} + 4 y^{2} - 16 = 0