y<= x^2+2

Lösung

y \leq x^{2} + 2

(h, k) = (0, 2), p = \frac{1}{4}

Schritte zur Lösung

y \leq x^{2} + 2

Rewrite

y \leq x^{2} + 2

in the standard form:

4 \cdot \frac{1}{4} (y - 2) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 2), p = \frac{1}{4}

(y - 4)^{2} = 3 (x + 4)

(x - 3)^{2} = 8 (y + 2)

(y - 3)^{2} = 16 (x + 1)

4 x^{2} + y = 4

(y - 4)^{2} = 20 (x + 5)